(2x-1)-(x^2-4x+4)=

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Solution for (2x-1)-(x^2-4x+4)= equation:


Simplifying
(2x + -1) + -1(x2 + -4x + 4) = 0

Reorder the terms:
(-1 + 2x) + -1(x2 + -4x + 4) = 0

Remove parenthesis around (-1 + 2x)
-1 + 2x + -1(x2 + -4x + 4) = 0

Reorder the terms:
-1 + 2x + -1(4 + -4x + x2) = 0
-1 + 2x + (4 * -1 + -4x * -1 + x2 * -1) = 0
-1 + 2x + (-4 + 4x + -1x2) = 0

Reorder the terms:
-1 + -4 + 2x + 4x + -1x2 = 0

Combine like terms: -1 + -4 = -5
-5 + 2x + 4x + -1x2 = 0

Combine like terms: 2x + 4x = 6x
-5 + 6x + -1x2 = 0

Solving
-5 + 6x + -1x2 = 0

Solving for variable 'x'.

Factor a trinomial.
(-5 + x)(1 + -1x) = 0

Subproblem 1

Set the factor '(-5 + x)' equal to zero and attempt to solve: Simplifying -5 + x = 0 Solving -5 + x = 0 Move all terms containing x to the left, all other terms to the right. Add '5' to each side of the equation. -5 + 5 + x = 0 + 5 Combine like terms: -5 + 5 = 0 0 + x = 0 + 5 x = 0 + 5 Combine like terms: 0 + 5 = 5 x = 5 Simplifying x = 5

Subproblem 2

Set the factor '(1 + -1x)' equal to zero and attempt to solve: Simplifying 1 + -1x = 0 Solving 1 + -1x = 0 Move all terms containing x to the left, all other terms to the right. Add '-1' to each side of the equation. 1 + -1 + -1x = 0 + -1 Combine like terms: 1 + -1 = 0 0 + -1x = 0 + -1 -1x = 0 + -1 Combine like terms: 0 + -1 = -1 -1x = -1 Divide each side by '-1'. x = 1 Simplifying x = 1

Solution

x = {5, 1}

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